Integrand size = 28, antiderivative size = 305 \[ \int \frac {\left (a+b x+c x^2\right )^{5/2}}{(b d+2 c d x)^{21/2}} \, dx=-\frac {\sqrt {a+b x+c x^2}}{836 c^3 d^5 (b d+2 c d x)^{11/2}}+\frac {\sqrt {a+b x+c x^2}}{2926 c^3 \left (b^2-4 a c\right ) d^7 (b d+2 c d x)^{7/2}}+\frac {5 \sqrt {a+b x+c x^2}}{8778 c^3 \left (b^2-4 a c\right )^2 d^9 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{114 c^2 d^3 (b d+2 c d x)^{15/2}}-\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}}+\frac {5 \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right ),-1\right )}{17556 c^4 \left (b^2-4 a c\right )^{7/4} d^{21/2} \sqrt {a+b x+c x^2}} \]
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Time = 0.19 (sec) , antiderivative size = 305, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {698, 707, 705, 703, 227} \[ \int \frac {\left (a+b x+c x^2\right )^{5/2}}{(b d+2 c d x)^{21/2}} \, dx=\frac {5 \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right ),-1\right )}{17556 c^4 d^{21/2} \left (b^2-4 a c\right )^{7/4} \sqrt {a+b x+c x^2}}+\frac {5 \sqrt {a+b x+c x^2}}{8778 c^3 d^9 \left (b^2-4 a c\right )^2 (b d+2 c d x)^{3/2}}+\frac {\sqrt {a+b x+c x^2}}{2926 c^3 d^7 \left (b^2-4 a c\right ) (b d+2 c d x)^{7/2}}-\frac {\sqrt {a+b x+c x^2}}{836 c^3 d^5 (b d+2 c d x)^{11/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{114 c^2 d^3 (b d+2 c d x)^{15/2}}-\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}} \]
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Rule 227
Rule 698
Rule 703
Rule 705
Rule 707
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}}+\frac {5 \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(b d+2 c d x)^{17/2}} \, dx}{38 c d^2} \\ & = -\frac {\left (a+b x+c x^2\right )^{3/2}}{114 c^2 d^3 (b d+2 c d x)^{15/2}}-\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}}+\frac {\int \frac {\sqrt {a+b x+c x^2}}{(b d+2 c d x)^{13/2}} \, dx}{76 c^2 d^4} \\ & = -\frac {\sqrt {a+b x+c x^2}}{836 c^3 d^5 (b d+2 c d x)^{11/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{114 c^2 d^3 (b d+2 c d x)^{15/2}}-\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}}+\frac {\int \frac {1}{(b d+2 c d x)^{9/2} \sqrt {a+b x+c x^2}} \, dx}{1672 c^3 d^6} \\ & = -\frac {\sqrt {a+b x+c x^2}}{836 c^3 d^5 (b d+2 c d x)^{11/2}}+\frac {\sqrt {a+b x+c x^2}}{2926 c^3 \left (b^2-4 a c\right ) d^7 (b d+2 c d x)^{7/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{114 c^2 d^3 (b d+2 c d x)^{15/2}}-\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}}+\frac {5 \int \frac {1}{(b d+2 c d x)^{5/2} \sqrt {a+b x+c x^2}} \, dx}{11704 c^3 \left (b^2-4 a c\right ) d^8} \\ & = -\frac {\sqrt {a+b x+c x^2}}{836 c^3 d^5 (b d+2 c d x)^{11/2}}+\frac {\sqrt {a+b x+c x^2}}{2926 c^3 \left (b^2-4 a c\right ) d^7 (b d+2 c d x)^{7/2}}+\frac {5 \sqrt {a+b x+c x^2}}{8778 c^3 \left (b^2-4 a c\right )^2 d^9 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{114 c^2 d^3 (b d+2 c d x)^{15/2}}-\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}}+\frac {5 \int \frac {1}{\sqrt {b d+2 c d x} \sqrt {a+b x+c x^2}} \, dx}{35112 c^3 \left (b^2-4 a c\right )^2 d^{10}} \\ & = -\frac {\sqrt {a+b x+c x^2}}{836 c^3 d^5 (b d+2 c d x)^{11/2}}+\frac {\sqrt {a+b x+c x^2}}{2926 c^3 \left (b^2-4 a c\right ) d^7 (b d+2 c d x)^{7/2}}+\frac {5 \sqrt {a+b x+c x^2}}{8778 c^3 \left (b^2-4 a c\right )^2 d^9 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{114 c^2 d^3 (b d+2 c d x)^{15/2}}-\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}}+\frac {\left (5 \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \int \frac {1}{\sqrt {b d+2 c d x} \sqrt {-\frac {a c}{b^2-4 a c}-\frac {b c x}{b^2-4 a c}-\frac {c^2 x^2}{b^2-4 a c}}} \, dx}{35112 c^3 \left (b^2-4 a c\right )^2 d^{10} \sqrt {a+b x+c x^2}} \\ & = -\frac {\sqrt {a+b x+c x^2}}{836 c^3 d^5 (b d+2 c d x)^{11/2}}+\frac {\sqrt {a+b x+c x^2}}{2926 c^3 \left (b^2-4 a c\right ) d^7 (b d+2 c d x)^{7/2}}+\frac {5 \sqrt {a+b x+c x^2}}{8778 c^3 \left (b^2-4 a c\right )^2 d^9 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{114 c^2 d^3 (b d+2 c d x)^{15/2}}-\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}}+\frac {\left (5 \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^4}{\left (b^2-4 a c\right ) d^2}}} \, dx,x,\sqrt {b d+2 c d x}\right )}{17556 c^4 \left (b^2-4 a c\right )^2 d^{11} \sqrt {a+b x+c x^2}} \\ & = -\frac {\sqrt {a+b x+c x^2}}{836 c^3 d^5 (b d+2 c d x)^{11/2}}+\frac {\sqrt {a+b x+c x^2}}{2926 c^3 \left (b^2-4 a c\right ) d^7 (b d+2 c d x)^{7/2}}+\frac {5 \sqrt {a+b x+c x^2}}{8778 c^3 \left (b^2-4 a c\right )^2 d^9 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{114 c^2 d^3 (b d+2 c d x)^{15/2}}-\frac {\left (a+b x+c x^2\right )^{5/2}}{19 c d (b d+2 c d x)^{19/2}}+\frac {5 \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right )\right |-1\right )}{17556 c^4 \left (b^2-4 a c\right )^{7/4} d^{21/2} \sqrt {a+b x+c x^2}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 5.17 (sec) , antiderivative size = 109, normalized size of antiderivative = 0.36 \[ \int \frac {\left (a+b x+c x^2\right )^{5/2}}{(b d+2 c d x)^{21/2}} \, dx=-\frac {\left (b^2-4 a c\right )^2 \sqrt {a+x (b+c x)} \operatorname {Hypergeometric2F1}\left (-\frac {19}{4},-\frac {5}{2},-\frac {15}{4},\frac {(b+2 c x)^2}{b^2-4 a c}\right )}{608 c^3 d^9 (b+2 c x)^8 (d (b+2 c x))^{3/2} \sqrt {\frac {c (a+x (b+c x))}{-b^2+4 a c}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(749\) vs. \(2(259)=518\).
Time = 6.34 (sec) , antiderivative size = 750, normalized size of antiderivative = 2.46
method | result | size |
elliptic | \(\frac {\sqrt {d \left (2 c x +b \right ) \left (c \,x^{2}+b x +a \right )}\, \left (-\frac {\left (16 a^{2} c^{2}-8 a \,b^{2} c +b^{4}\right ) \sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}{311296 c^{13} d^{11} \left (x +\frac {b}{2 c}\right )^{10}}-\frac {\left (4 a c -b^{2}\right ) \sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}{29184 c^{11} d^{11} \left (x +\frac {b}{2 c}\right )^{8}}-\frac {67 \sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}{642048 c^{9} d^{11} \left (x +\frac {b}{2 c}\right )^{6}}-\frac {\sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}{46816 c^{7} \left (4 a c -b^{2}\right ) d^{11} \left (x +\frac {b}{2 c}\right )^{4}}+\frac {5 \sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}{35112 c^{5} \left (4 a c -b^{2}\right )^{2} d^{11} \left (x +\frac {b}{2 c}\right )^{2}}+\frac {5 \left (\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}\right ) \sqrt {\frac {x +\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}}{\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}}}\, \sqrt {\frac {x +\frac {b}{2 c}}{-\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b}{2 c}}}\, \sqrt {\frac {x -\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}}{-\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}}}\, F\left (\sqrt {\frac {x +\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}}{\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}}}, \sqrt {\frac {-\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}}{-\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b}{2 c}}}\right )}{17556 c^{3} \left (4 a c -b^{2}\right )^{2} d^{10} \sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}\right )}{\sqrt {d \left (2 c x +b \right )}\, \sqrt {c \,x^{2}+b x +a}}\) | \(750\) |
default | \(\text {Expression too large to display}\) | \(1843\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.35 (sec) , antiderivative size = 810, normalized size of antiderivative = 2.66 \[ \int \frac {\left (a+b x+c x^2\right )^{5/2}}{(b d+2 c d x)^{21/2}} \, dx=\frac {5 \, \sqrt {2} {\left (1024 \, c^{10} x^{10} + 5120 \, b c^{9} x^{9} + 11520 \, b^{2} c^{8} x^{8} + 15360 \, b^{3} c^{7} x^{7} + 13440 \, b^{4} c^{6} x^{6} + 8064 \, b^{5} c^{5} x^{5} + 3360 \, b^{6} c^{4} x^{4} + 960 \, b^{7} c^{3} x^{3} + 180 \, b^{8} c^{2} x^{2} + 20 \, b^{9} c x + b^{10}\right )} \sqrt {c^{2} d} {\rm weierstrassPInverse}\left (\frac {b^{2} - 4 \, a c}{c^{2}}, 0, \frac {2 \, c x + b}{2 \, c}\right ) + 2 \, {\left (2560 \, c^{10} x^{8} + 10240 \, b c^{9} x^{7} - 5 \, b^{8} c^{2} - 10 \, a b^{6} c^{3} - 28 \, a^{2} b^{4} c^{4} + 4928 \, a^{3} b^{2} c^{5} - 14784 \, a^{4} c^{6} + 128 \, {\left (143 \, b^{2} c^{8} - 12 \, a c^{9}\right )} x^{6} + 128 \, {\left (149 \, b^{3} c^{7} - 36 \, a b c^{8}\right )} x^{5} + 4 \, {\left (2691 \, b^{4} c^{6} + 2312 \, a b^{2} c^{7} - 7504 \, a^{2} c^{8}\right )} x^{4} + 8 \, {\left (211 \, b^{5} c^{5} + 3272 \, a b^{3} c^{6} - 7504 \, a^{2} b c^{7}\right )} x^{3} - 2 \, {\left (359 \, b^{6} c^{4} - 6840 \, a b^{4} c^{5} + 7728 \, a^{2} b^{2} c^{6} + 19712 \, a^{3} c^{7}\right )} x^{2} - 2 \, {\left (45 \, b^{7} c^{3} + 88 \, a b^{5} c^{4} - 7280 \, a^{2} b^{3} c^{5} + 19712 \, a^{3} b c^{6}\right )} x\right )} \sqrt {2 \, c d x + b d} \sqrt {c x^{2} + b x + a}}{35112 \, {\left (1024 \, {\left (b^{4} c^{15} - 8 \, a b^{2} c^{16} + 16 \, a^{2} c^{17}\right )} d^{11} x^{10} + 5120 \, {\left (b^{5} c^{14} - 8 \, a b^{3} c^{15} + 16 \, a^{2} b c^{16}\right )} d^{11} x^{9} + 11520 \, {\left (b^{6} c^{13} - 8 \, a b^{4} c^{14} + 16 \, a^{2} b^{2} c^{15}\right )} d^{11} x^{8} + 15360 \, {\left (b^{7} c^{12} - 8 \, a b^{5} c^{13} + 16 \, a^{2} b^{3} c^{14}\right )} d^{11} x^{7} + 13440 \, {\left (b^{8} c^{11} - 8 \, a b^{6} c^{12} + 16 \, a^{2} b^{4} c^{13}\right )} d^{11} x^{6} + 8064 \, {\left (b^{9} c^{10} - 8 \, a b^{7} c^{11} + 16 \, a^{2} b^{5} c^{12}\right )} d^{11} x^{5} + 3360 \, {\left (b^{10} c^{9} - 8 \, a b^{8} c^{10} + 16 \, a^{2} b^{6} c^{11}\right )} d^{11} x^{4} + 960 \, {\left (b^{11} c^{8} - 8 \, a b^{9} c^{9} + 16 \, a^{2} b^{7} c^{10}\right )} d^{11} x^{3} + 180 \, {\left (b^{12} c^{7} - 8 \, a b^{10} c^{8} + 16 \, a^{2} b^{8} c^{9}\right )} d^{11} x^{2} + 20 \, {\left (b^{13} c^{6} - 8 \, a b^{11} c^{7} + 16 \, a^{2} b^{9} c^{8}\right )} d^{11} x + {\left (b^{14} c^{5} - 8 \, a b^{12} c^{6} + 16 \, a^{2} b^{10} c^{7}\right )} d^{11}\right )}} \]
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Timed out. \[ \int \frac {\left (a+b x+c x^2\right )^{5/2}}{(b d+2 c d x)^{21/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (a+b x+c x^2\right )^{5/2}}{(b d+2 c d x)^{21/2}} \, dx=\int { \frac {{\left (c x^{2} + b x + a\right )}^{\frac {5}{2}}}{{\left (2 \, c d x + b d\right )}^{\frac {21}{2}}} \,d x } \]
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\[ \int \frac {\left (a+b x+c x^2\right )^{5/2}}{(b d+2 c d x)^{21/2}} \, dx=\int { \frac {{\left (c x^{2} + b x + a\right )}^{\frac {5}{2}}}{{\left (2 \, c d x + b d\right )}^{\frac {21}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\left (a+b x+c x^2\right )^{5/2}}{(b d+2 c d x)^{21/2}} \, dx=\int \frac {{\left (c\,x^2+b\,x+a\right )}^{5/2}}{{\left (b\,d+2\,c\,d\,x\right )}^{21/2}} \,d x \]
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